Question

if 5 th term of a G. p is 32 and common ratio is 2, then find 1 st term





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Answer 1

Step-by-step explanation:

For GP

$t = ar {}^{n - 1} \\ here \: n = 5 \\ \\ r = 2 \\ \\ t = 32$

Substitute these values in the given formula.

$32 = a(2) {}^{5 - 1} \\ 32 = a2 {}^{4} \\ 32 = 16a \\ a = 2$