If 5 times of 21st term of an AP is equal to its 5th term ,then show that 25th term is zero
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given: 5 * ^a25 = ^a5
to show: a25=0
^an = a+(n-1)d
^a21= a+20d.........(1)
^a5=a+4d......(2)
acco to questn,
5 * ^a25 = ^a5
putting values of ^a25 & ^a5 from (1)&(2), we get,
5(a+20d)= a+4d
5a + 100d = a+4d
5a-a+100 - d= 0
4a + 96d = 0
4(a+ 24d = 0)
a+24d = 0
^a25= a+24d
^a25= 0
hence proved.
to show: a25=0
^an = a+(n-1)d
^a21= a+20d.........(1)
^a5=a+4d......(2)
acco to questn,
5 * ^a25 = ^a5
putting values of ^a25 & ^a5 from (1)&(2), we get,
5(a+20d)= a+4d
5a + 100d = a+4d
5a-a+100 - d= 0
4a + 96d = 0
4(a+ 24d = 0)
a+24d = 0
^a25= a+24d
^a25= 0
hence proved.
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