Question

If 5 times of a positive whole number is less by 3 than twice of its
square, then find the times?​​

Answer 1

Answer:

Answer

Let us consider the number be 'x'

So according to the question,

5x=2x

2

−3

2x

2

−3−5x=0

2x

2

−5x−3=0

Let us factorize,

2x

2

−6x+x−3=0

2x(x−3)+1(x−3)=0

(x−3)(2x+1)=0

So

(x−3)=0 or (2x+1)=0

x=3 or 2x=−1

x=3 or x=−1/2

Answer 2

Answer :

The answer is 3

Explanation :

Let the number be x then 5x + 3 = 2x^2

This becomes a quadratic equation that is

2x^2 -5x - 3 = 0

2x^2 - 6x + x -3 =0

2x ( x-3 ) + 1 (x - 3 ) = 0

So (2x +1)(x-3) = 0

So by using common sense we can say that one of the two has to be zero then only can the product be zero so two cases now arise either

2x+1 = 0 wherein x=-1/2

OR

x-3=0 wherein x= 3

Now as the question states the value of x is a positive and a whole number then we can reject the value of -1/2 hence we get that the value of x is 3 . So the number being talked about in the question above is three .