If 5 times the 5th term of an ap is equal to 8 times at 8 term so that its 13 term is zero
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Let 'a' be first term and 'd' be common difference.
Given 5a5=8a8
5(a+4d)=8(a+7d)(since an=a+(n-1)d)
5a+20d=8a+56d
a=-12d
a+12d=0-----------(1)
a13=a+12d=0 (using (1))
Therefore, value of 13th term is zero.
Given 5a5=8a8
5(a+4d)=8(a+7d)(since an=a+(n-1)d)
5a+20d=8a+56d
a=-12d
a+12d=0-----------(1)
a13=a+12d=0 (using (1))
Therefore, value of 13th term is zero.
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