if 5 to the power 2 X + 1 divided by 25 is equal to 125 find the value of x
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Hi there!
Here's the answer:
•°•°•°•°•°•<><><<><>><><>•°•°•°•°•°•
5^(2x+1) ÷ 25
=> 5^(2x+1) ÷ 5²
°•° a^m ÷ a^n = a ^(m-n)
=> 5^(2x+1-2)
= 5^(2x-1)
Given this result is 125.
=> 5^(2x-1) = 125
To find the values of x, make bases equal on either sides
Which means express 125 as 5 to the power of something.
5×5×5 = 125
=> 125 = 5³
•°• 5^(2x-1) = 5^(3).
°•° Bases are equal, powers are also equal
(or)
°•° If a^m = a^n, then m = n
Equate powers on both sides
=> 2x-1 = 3
=> 2x = 4
=> x = 2
•°• Value of x = 2.
•°•°•°•°•°•<><><<><>><><>•°•°•°•°•°•
¢#£€®$
:)
Hope it helps
Here's the answer:
•°•°•°•°•°•<><><<><>><><>•°•°•°•°•°•
5^(2x+1) ÷ 25
=> 5^(2x+1) ÷ 5²
°•° a^m ÷ a^n = a ^(m-n)
=> 5^(2x+1-2)
= 5^(2x-1)
Given this result is 125.
=> 5^(2x-1) = 125
To find the values of x, make bases equal on either sides
Which means express 125 as 5 to the power of something.
5×5×5 = 125
=> 125 = 5³
•°• 5^(2x-1) = 5^(3).
°•° Bases are equal, powers are also equal
(or)
°•° If a^m = a^n, then m = n
Equate powers on both sides
=> 2x-1 = 3
=> 2x = 4
=> x = 2
•°• Value of x = 2.
•°•°•°•°•°•<><><<><>><><>•°•°•°•°•°•
¢#£€®$
:)
Hope it helps
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