If 5 x is equals to sec theta and 5 upon x is equal to 10 theta find 5( x square minus one upon x square).
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Answered by
5
5x = sec theta
5/X = tan theta
sex square theta=1+ tan square theta
25x square= 1+25/xsquare
5(X square -1/x square )=1/5
5/X = tan theta
sex square theta=1+ tan square theta
25x square= 1+25/xsquare
5(X square -1/x square )=1/5
Answered by
4
5x=sec theta
5/x=10theta
5(x²-1)/x²
5(x²-1)/(x)(x)= tan theta (x²-1)/x
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