if 5, x, y, 26 are in AP then find X and Y
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Given,
5, x, y, 26 are in A.P.
∴ x - 5 = y - x = 26 - y
Now,
x-5 = y-x
or 2x - y = 5 ..........(1)
And,
y-x = 26-y
or 2y -x = 26 ..............(2)
(1) × 2 + (2), we get
4x -2y + 2y - x = 10 + 26
or 3x = 36
or x = 12
Now, (1)⇒ 2x - y = 5
⇒2×12 -y = 5
⇒ 24 -y = 5
⇒y = 19
Thus, x = 12 and y = 19
5, x, y, 26 are in A.P.
∴ x - 5 = y - x = 26 - y
Now,
x-5 = y-x
or 2x - y = 5 ..........(1)
And,
y-x = 26-y
or 2y -x = 26 ..............(2)
(1) × 2 + (2), we get
4x -2y + 2y - x = 10 + 26
or 3x = 36
or x = 12
Now, (1)⇒ 2x - y = 5
⇒2×12 -y = 5
⇒ 24 -y = 5
⇒y = 19
Thus, x = 12 and y = 19
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