if 50 is subtracted from twice the greater of two numbers,it gives the other number.if 17 is subtracted from twice the smaller number,it gives the larger number .find the number
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according to the question let the greater one be x and smaller one be y
2x-50=y
2y-17=x
y= 2x-50
2y=x+17 (transpose)
2y= 4x-100
2y=x+17
subtract
3x-117=0
3x-=117
x=117/3=39
x=39
to find y
2y-17=39
2y=56
y=56/2=28
y=28
to verify
2x-50=28
78-50=28
2y-17=39
56-17=39
Therefore verified the greater number is 39 and the smaller one is 28
HOPE THIS HELPS
PLS MARK AS BRAINLIEST
2x-50=y
2y-17=x
y= 2x-50
2y=x+17 (transpose)
2y= 4x-100
2y=x+17
subtract
3x-117=0
3x-=117
x=117/3=39
x=39
to find y
2y-17=39
2y=56
y=56/2=28
y=28
to verify
2x-50=28
78-50=28
2y-17=39
56-17=39
Therefore verified the greater number is 39 and the smaller one is 28
HOPE THIS HELPS
PLS MARK AS BRAINLIEST
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