Question

If 50 men can do a piece of work in 20days how many men will do it 10days​

Answer 1

It is given that 50 men can do a piece of work in 20 days. Let the number of men required to complete the work in 10 days be (m) men.

x (days) || 10 || 20

y (men) || m || 50

∴ It is a case of indirect proportion, where,

x ∝ 1/y ⇒ xy = k (constant)

So, 10 × m = 20 × 50

⇒ 10 m = 1000

⇒ m = 100.

Thus, the number of men required in 100.

Answer 2

Answer:

100 men

Step-by-step explanation:

In 20 days 50 men can do a piece of work

in 1 day 50*20 men can do this work

in 10 days (50*20)/10 men can do this work

= 1000/10

= 100 men can do this work