if 50 milli of ampere current is passed through copper coulometer for 60 min calculate the amount of copper deposited
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ExpFaraday's law of electrolysis.
As
W= Ite/F
F= 965900 C
t=45 x 60 sec
e for copper if taken in copper sulphate then
e= Mw.t of Salt /charge on cation
e= (63.5+96)/2
e=79.8
So
W=5 x (45 x 60) 79.8/96500
W=11.1 grams (of copper deposited on cathode or librated from anode).lanation:
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