Question

If 50% of 2:3 solution of milk and water is replaced with water, then the concentration of the solution is reduced by

Answer 1

Hey Dear,

◆ Answer -

Concentration of solution is reduced by 20 %

◆ Explaination -

Let x be some common multiplier such that -

Milk = 2x

Water = 3x

Initial concentration of the solution -

Ci = 2x / (2x+3x) × 100

Ci = 40 %

Later 50% soln is replaced with water.

Milk = 2x - x = x

Water = 3x - 3x/2 + 5x/2 = 4x

Now, final concentration of solution is -

Cf = x / (x + 4x) × 100

Cf = 20 %

So concentration is reduced by -

∆C = Cf - Ci

∆C = 40% - 20%

∆C = 20 %

Therefore, conc of solution is reduced by 20 %.

Thanks dear...

Answer 2

Answer:

therefore the concentration is reduced by 20%