If p and q are zeros of x^2+mx+n^2+a then find the value of p2+q2+pq
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Solution :
Let f(x) = x²+mx+n²+a
Compare f(x) with Ax² + Bx + C , we get
A = 1 , B = m , C = n²+a
It is given that ,
p, q are zeros of f(x) ,
p + q = -B/A = -m ----( 1 )
pq = C/A = ( n² + a ) ----( 2 )
p² + q² + pq = ( p+q )² - pq
= ( - m )² - ( n² + a )
= m² - n² - a
•••••
Let f(x) = x²+mx+n²+a
Compare f(x) with Ax² + Bx + C , we get
A = 1 , B = m , C = n²+a
It is given that ,
p, q are zeros of f(x) ,
p + q = -B/A = -m ----( 1 )
pq = C/A = ( n² + a ) ----( 2 )
p² + q² + pq = ( p+q )² - pq
= ( - m )² - ( n² + a )
= m² - n² - a
•••••
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