If 500 ml of gas A at 400 torr and 666.6 ml of B at 600 torr are
placed in a 3 litre flask, the pressure of the system will be
(a) 200 torr (b) 100 torr (c) 550 torr (d) 366 torr
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Answered by
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If 500 ml of gas A at 400 torr and 666.6 ml of B at 600 torr are
placed in a 3 litre flask, the pressure of the system will be
(a) 200 torr
(b) 100 torr
(c) 550 torr (
d) 366 torr
Answered by
8
The pressure of the system will be
(a) 200 torr
According to Boyle's Law, we know that:
P₁V₁ = P₂V₂
Here, P₁ = 400 torr
V₁ = 500 mL = 0.5 L [1mL = 0.001L]
V₂ = 3L
To find P₂
P₂ = (P₁V₁ )/V₂
= (400*0.5)/3 torr
= 66.67 torr
Again P₁' = 600 torr
V₁' = 666.6 mL = 0.6666 L
So, P₂' = (P₁'V₁' )/V₂
= (600*0.6666)/3 torr
= 133.32 torr
Total pressure = P₂ + P₂'
= (66.67 + 133.32) torr
= 200 torr
Option (a) is correct.
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