Question

The van der Waal’s constant ‘a’ for four gases P, Q, R and S
are 4.17, 3.59, 6.71 and 3.8 atm L² mol⁻² respectively.
Therefore, the ascending order of their liquefaction is
(a) R < P < S < Q (b) Q < S < R < P
(c) Q < S < P < R (d) R < P < Q < S

Answer 1

Answer:

The van der Waal’s constant ‘a’ for four gases P, Q, R and S

are 4.17, 3.59, 6.71 and 3.8 atm L² mol⁻² respectively.

Therefore, the ascending order of their liquefaction is

(a) R < P < S < Q

(b) Q < S < R < P

(c) Q < S < P < R

(d) R < P < Q < S

Answer 2

The ascending order of liquefaction of the given gases as per their Vander Waal’s constant ‘a’ is (c) Q < S < P < R.

Explanation:

• The concept involved in the given scenario is that the liquefaction of the gases is directly proportional to their value of Vander Waal’s constant ‘a.
• It means that, if Vander Waal’s constant ‘a’ increases, the liquefaction value increases and vice versa.
• As per the given condition, the Vander Waal’s constant ‘a’ for given gases are as follows:

1. P - 4.17
2. Q - 3.59
3. R - 6.71
4. S - 3.8

• As per the value if they are arranged in increasing order it gives the following order:

3.59 < 3.8 < 4.17 < 6.71

• When the gases with the corresponding value is arranged it gives the following order:

Q < S < P < R

• Thus the ascending order of their liquefaction is (c) Q < S < P < R.

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