Question

If 50g of water at 20c temperature and 50g of water 40c temperature are mixed, what is the final temperature of the mixture of

Answer 1

mass of hot water =50g(m1)

temperature=40°c(T1)

mass of cold water=50g(m2)

temperature=20°c(T2)

final temperature=m1T1+m2T2/m1+m2

=50×40+50×20/50+50

=2000+1000/100

=3000/100

=30℃

final temperature=30℃

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Answer 2

GiveN :-

• If 50g of water at 20°C temperature and 50g of water at 40C temperature are mixed.

To FinD :-

• The final temperature of the mixture.

SolutioN :-

Here , 50g of water at 20°C temperature and 50g of water at 40°C temperature are mixed and we need to find the final temperature of the mixture. Let us denote ,

$\qquad\red{\frak{ Let }}\begin{cases}\sf Mass _1 = 50 g \\\sf Mass_2 = 50g \\\sf Temperature_1 = 20^oC \\\sf Temperature_2 = 40^o C \end{cases}$

Now here we can find the final temperature as ,

$\sf:\implies \pink{ Temperature_{(Final)}=\dfrac{(m_1)(t_1)+(m_2)(t_2)}{m_1+m_2}}\\\\\sf:\implies T_{(final)}= \dfrac{(50g)(20^oC)+(50g)(40^oC)}{50g+50g} \\\\\sf:\implies T_{(final)}=\dfrac{1000 + 2000}{100} ^oC \\\\\sf:\implies T_{(final)}=\dfrac{3000 ^o C }{100}\\\\\sf:\implies\underset{\blue{\sf Required\ Temperature}}{\underbrace{\boxed{\pink{\frak{ Temperature_{(final)}= 30^{\circ} C }}}}}$