Question

If 51, 68, 81 and 108 are in proportion, then
a)write the value T1 & T3
b)mention the middle terms.

Answer 1

Answer:

Let the third term x. 51×108 = 5508. 5508/68=81. You can take help from this image. Please mark me as a brainlist.

Answer 2

Answer:

Given

First term =51

Second term =68

fourth term =108

Let the third term be x

Such that the proportion is 51:68::x:108

We know that

Product of extremes = product of means

⇒(51×108)=(68×x)

⇒(68×x)=(51×108)

⇒68x=5508

⇒x=

68

5508

∴x=81

Step-by-step explanation:

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