If 51, 68, 81 and 108 are in proportion, then
a)write the value T1 & T3
b)mention the middle terms.
Answers
Answered by
1
Answer:
Let the third term x. 51×108 = 5508. 5508/68=81. You can take help from this image. Please mark me as a brainlist.
Answered by
1
Answer:
Given
First term =51
Second term =68
fourth term =108
Let the third term be x
Such that the proportion is 51:68::x:108
We know that
Product of extremes = product of means
⇒(51×108)=(68×x)
⇒(68×x)=(51×108)
⇒68x=5508
⇒x=
68
5508
∴x=81
Step-by-step explanation:
Mark as branliest please
Similar questions