Question

if 520 ml of H2 is collected over Water at 28 degree Celsius and the atmospheric pressure is 1 ATM if vapour pressure of water at 28 degree celsius is 28.3 mmhg then the amount of zn in grams taken at start of the reaction is
Zn+2HCl----->ZnCl2+H2​

Answer 1

Answer:

Explanation:

Given If 520 ml of H2 is collected over Water at 28 degree Celsius and the atmospheric pressure is 1 ATM if vapour pressure of water at 28 degree celsius is 28.3 mmhg then the amount of zn in grams taken at start of the reaction is

We know that  

P h2 = PT – Ph20 = 1 atm – 0.037 atm

                             = 0.963 atm

n h2 = Ph2 V / RT  

          = 0.963 atm x 0.520 L / 0.0821 L atm / mol K x 301

         = 0.02 mol h2

            = 0.02 mol Zn

So 0.02 mol Zn x 65.39 g/mol

        = 1.33 g Zn