if 54g of aluminium reacts with 160g of oxygen. find out the amount of product formed
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Answered by
2
Answer:
Number of atom n = mass ÷ molar mass
Number of A atom = 54÷27 == 2 atom of AL
Molecule of ALO2
= 3 × 6.022 × 10 (23)
= 18.066 × (23)
Now, mass of ALO2 is
Mass of Ak mol. + mass of O2 mol.
= 54 + 160
= 214 U mass of ALO2
Answered by
0
Answer:
Explanation:in question
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