Math, asked by nachiketstpatil8932, 8 months ago

If 5897x is divisible by 3,find all the possible values of digit x

Answers

Answered by sahilagarwal6789
0

Answer:

x=1,4,7,

Step-by-step explanation:

the divisiblity test of 3 is the sum of all the

digits in a number should be a divisible by 3 or it should be a multiple of 3

so,

5+8+9+7+x=29

which means that the only possible positive number can be 1,4 or 7.

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Answered by cutie08
1

Answer:

1, 4 and 7

Step-by-step explanation:

Divisibility rule of 3 = the sum of digits will be divisible by 3.

Digit = 5897x

Sum of digits = 5 + 8 + 9 + 7 + x = 29 + x

We have to choose all the single number values through which the sum of digits will be divisible by 3.

So,

Value of x =

1 => 29 + 1 = 30 which is divisible by 3.

4 => 29 + 4 = 33 which is divisible by 3.

7 => 29 + 7 = 36 which is divisible by 3.

So, all the values are = 1, 4 and 7.

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