If 5cos A=7sin A find sin A and cos A
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Its easy.
Sin A/Cos A=5/7
Tan A=5/7=perpendicular/base
Let perpendicular(p)=5x
Base(b)=7x
Hypotenuse(h)=√(p^2+b^2)
h=√60x
Sin A=p/h=5x/√60x=5/√60
similarly for Cos A.
Sin A/Cos A=5/7
Tan A=5/7=perpendicular/base
Let perpendicular(p)=5x
Base(b)=7x
Hypotenuse(h)=√(p^2+b^2)
h=√60x
Sin A=p/h=5x/√60x=5/√60
similarly for Cos A.
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