if 5cot0=12 find the value of cosec0+cos0
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Answer:
229/ 65
Step-by-step explanation:
You have used angle as 0. So, I am also going to use angle as 0.
5cot0=12
now, cot0= 12/5
which means cot0 is Base(B)/ Perpendicular(P), B=12, P=5
Now, we will use Pythagoras theorem,
H^2= P^2+B^2
H^2= 5^2+ 12^2
H^2= 25+ 144= 169
H=13
cosec0+ cos0= H/P+ B/H
=13/5+ 12/13
=169+60/ 65
=229/65
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