If Ā= 5i+7j-3k and B=15i+21j+ak are parallel vectors then the value of a is
(a)-3
(b) 9
(©)-9
(d)3
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Answer:
a I think conform with someone else
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a=-9
As 5i+7j-3k= z ( 15i+21j+ak)
15z=5
Z=1/3
-3= a z
-3= 1/3z
So z=-9
As 5i+7j-3k= z ( 15i+21j+ak)
15z=5
Z=1/3
-3= a z
-3= 1/3z
So z=-9
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