If 5th and 15th term of ap are 13 and -17 find sum of 21 terms
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Answer:
a5=13, a15=-17
a+4d=13 1.
a+14d=-17 2.
Subtract equation 1. from 2.
a + 14d = -17
a + 4d = 13
(-) (-) (-)
10d = -30
d = -30/10
d = -3
Put the value of d in eq. 1.
a + 4d = 13
a + 4×-3 = 13
a - 12 = 13
a = 13+ 12
a = 25
Sn = n/2 [2a + (n-1) d]
S21= 21/2 [2×25 + (21-1) ×-3]
S21= 21/2 (50 + 20 × -3)
S21= 21/2 (50 -60)
S21= 21/2 ×-10
S21= 21 ×-5
S21= -105
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