Math, asked by Sweety1114, 1 year ago

If 5th term and 8th term of a gp be 48and384 respectively find the gp if terms of gp are real number

Answers

Answered by Srividyashivakumar
28
T5=48. T8=384
ar^4=48. ar^7=384
ar^7/ar^4=384/48
r^3=8
r=2. ar^3=48
a*8=48
a=6
The GP is 6, 12, 24, 48.........
Answered by amikkr
6

The given GP becomes 3,5,12,24,...

  • The 5th term of the GP is 48 and the 8th term of the GP is 384.
  • nth term of the GP is given by the formula t_n = ar^{n-1}.
  • Now,

t_5 = ar^{5-1}

48= ar^{4}    (Equation 1)

t_8 = ar^{8-1}

384 = ar^{7}        (Equation 2)

  • Now dividing equation 2 by equation 1 , we get

8 = r³

r = 2

  • Now substituting the value of d in equation 1 we get,

ar^4 = 48

a3^4 = 48

a = 3.

  • Now the given series in GP becomes a , ar, ar² , ar³ ,...
  • The given GP is 3 , 6 , 12 , 24 , .....
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