Find the value of k for which the equation ( k-12)x^2+2(k-12)x+2=0 has real and equal roots
Answers
Answered by
11
If it has equal n real roots thn
b²-4ac=0
b=2k-24
a=k-12
c=2
(2k-24)²-4(k-12)(2)=0
4k²-96k+576-(8k-96)=0
4k²-96k+576-8k+96=0
4k²-104k+672=0
Divide by 4
k²-26k+168=0
Then using factotization
k²-12k-14k+168=0
k(k-12)-14(k-12)=0
(k-12)(k-14)=0
Then the values of k are '12' and '14'
Ans:12,14
Plz mark as brainlist
b²-4ac=0
b=2k-24
a=k-12
c=2
(2k-24)²-4(k-12)(2)=0
4k²-96k+576-(8k-96)=0
4k²-96k+576-8k+96=0
4k²-104k+672=0
Divide by 4
k²-26k+168=0
Then using factotization
k²-12k-14k+168=0
k(k-12)-14(k-12)=0
(k-12)(k-14)=0
Then the values of k are '12' and '14'
Ans:12,14
Plz mark as brainlist
Similar questions