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ar ABCD = 30cm ^2
ar AEB = 1/2 ar ABCD ( by a theorem )
ar AEB = 15 cm ^2
ar ADE + ar BEC = ar AEB ( by a theorem )
Therefore ,
ar ADE + ar BEC = 15 cm ^2
ar AEB = 1/2 ar ABCD ( by a theorem )
ar AEB = 15 cm ^2
ar ADE + ar BEC = ar AEB ( by a theorem )
Therefore ,
ar ADE + ar BEC = 15 cm ^2
Akshit1111111:
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