a man and a boy can complete a work together in 24 days. if the last six days man alone does the work then it is completed in 26 days. how long the boy will take to complete the work alone?
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Work done by man and boy in 1 day = 1/24
Work done by man and boy in 20 days = 5/6
Work left = 1/6
Let us take work done by man in a day to be x.
Work done by man in 6 days = 6x
Work left or the work which is finished by man alone = 1/6
=> 6x = 1/6
=>x = 1/36
Work done by man in 1 day = 1/36
Work done by boy in 1 day = Work done by man and boy in 1 day - Work done by man in 1 day
=1/24 -1/36
=1/72
Therefore the boy will take 72 days to complete the work.
Work done by man and boy in 20 days = 5/6
Work left = 1/6
Let us take work done by man in a day to be x.
Work done by man in 6 days = 6x
Work left or the work which is finished by man alone = 1/6
=> 6x = 1/6
=>x = 1/36
Work done by man in 1 day = 1/36
Work done by boy in 1 day = Work done by man and boy in 1 day - Work done by man in 1 day
=1/24 -1/36
=1/72
Therefore the boy will take 72 days to complete the work.
arjunchristopher:
thanks
Answered by
1
Answer:
Ans is 72 day's
Step-by-step explanation:
4 day's of boy= 2 day's of man
boy:man=1:2
hence, TW=3*24=72
thus, boy alone will take 72/1=72 day's
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