if 5th term ap is 26 & 10th term is 51 determine 15th term
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himanshucchoudhary:
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5th term of an AP = 26
a5 = 26
a + 4d = 26 --------------- equation number 1
10th term of an AP = 51
a10 = 51
a + 9d = 51 ---------------- equation number 2
by adding equation number 1 and 2 we will get
5d = 25
d = 5 ----------- putting in equation 1
a + 4d = 26
a + 4×5 = 26
a = 26 - 20
a = 6
a15 = a + 14d
= 6 + 14 × 5
= 6 + 70
= 76.
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a5 = 26
a + 4d = 26 --------------- equation number 1
10th term of an AP = 51
a10 = 51
a + 9d = 51 ---------------- equation number 2
by adding equation number 1 and 2 we will get
5d = 25
d = 5 ----------- putting in equation 1
a + 4d = 26
a + 4×5 = 26
a = 26 - 20
a = 6
a15 = a + 14d
= 6 + 14 × 5
= 6 + 70
= 76.
If you find my answer helpful please mark it as a brainliest.
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