Question

two adjacent sides of a parallelogram are in the ratio 3:8 and its perimeter is 110 cm. find the sides of parallelogram

Answer 1

$\mathbb{ SOLUTION }$:

Let, ABCD be the parallelogram.

Given : Two adjacent sides of the parallelogram are in ratio 3:8.
And,
perimeter of the parallelogram is 110cm


AD = 3x cm
DC = 8x cm

AD = BC and DC = AB [ $\therefore$ Opposite sides of parallelogram are equal ]

So,
Perimeter of the parallelogram
=> AB + BC + DC + AD = 110 cm

=> 8x + 3x + 8x + 3x = 110

=> 22x = 110

=> x = $\frac{110}{22}$

=> x = 5

So,
AB = 8x = 8*5 = 40 cm
BC = 3x = 3*5 = 15 cm
DC = 8x = 8*5 = 40 cm
AD = 3x = 3*5 = 15 cm

Answer 2

Answer:

AB = 8x = 8*5 = 40 cm

BC = 3x = 3*5 = 15 cm

DC = 8x = 8*5 = 40 cm

AD = 3x = 3*5 = 15 cm

Step-by-step explanation:

SOLUTION :

Let, ABCD be the parallelogram.

Given : Two adjacent sides of the parallelogram are in ratio 3:8.

And,

perimeter of the parallelogram is 110cm

AD = 3x cm

DC = 8x cm

AD = BC and DC = AB [ \therefore∴ Opposite sides of parallelogram are equal ]

So,

Perimeter of the parallelogram

=> AB + BC + DC + AD = 110 cm

=> 8x + 3x + 8x + 3x = 110

=> 22x = 110

=> x = \frac{110}{22}22110

=> x = 5

So,

AB = 8x = 8*5 = 40 cm

BC = 3x = 3*5 = 15 cm

DC = 8x = 8*5 = 40 cm

AD = 3x = 3*5 = 15 cm