Question

if (5x+2y):7x+4y)=13:20 find x:y​

Answer 1

Answer:

5x+2y/7x+4y =13/20

5x+2y=13 and 7x+4y = 20

now subtract 5x+2y=13 from 7x+4y=20

(7x-10x) +( 4y-4y)+(20-26)

-3x+0y= -6

-3x= -6

x= 6/3

x= 2

substitute x=2 in 5x+2y=13

5(2)+2y=13

10+2y=13

2y =13-10

2y=3

y=3/2