Question

If (5x-4y)=7, xy=8
Then find 125x³-64y³



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Answer 1

$125x {}^{3} - 64y {}^{3}$

$= (5x) {}^{3} - (4y) {}^{3}$

use identity of a^3 -b^3

then ,

$= (5x - 4y)(25 x{}^{2} + 16y {}^{2} + 20xy)$

$= 7(25x {}^{2} + 16y {}^{2} + 20x8)$

$= 7(327 + 160)$

$\: = 7(487) = 1447$

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Answer 2

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