If 5x = sec thita and 5/x = tan thita, find the value of 5(x^2+1/x^2)
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Answer:sec²θ - tan²θ = 1
=> (5x)² - (5/x)² = 1
=> 25x² - 25/x² = 1
=> 25 ( x² - 1/x² ) = 1
=> 5 x 5 ( x² - 1/x² ) = 1
=> 5 x ( x² - 1/x² ) = 1/5.
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