Question

if 5x=secA and 5/x=tanA,find the value of 5[$x^{2}$-1/$x^{2}$/]

Answer 1

5x=secA => 25x^2 = sec^2 A and 5/x= tan A => 25/x^2 = tan^2 A now subtracting them we get 25 [ x^2- 1/x^2] = sec^2A - tan^2 A => 25[x^2-1/x^2]=1 => 5(x^2-1/x^2) = 1/5 answer