If 6^(2n+1) - 36 = 6^3, then value of n is
Answers
Answered by
13
Hi.
Here is your answer----------
Given------------
6^(2n+1) - 36 = 6^3
We know, 6 ^2 = 36, therefore,
6^(2n+1) - 6^2 = 6^3
Since, bases of all the three terms are same(,i.e.,6), thus, power should be equated.
(2n+1) - 2 = 3
2n + 1 = 3 + 2
2n = 5 -1
2n = 4
n = 2
Thus, value of n is 2
Hope it will help u.
Have a nice day.
Here is your answer----------
Given------------
6^(2n+1) - 36 = 6^3
We know, 6 ^2 = 36, therefore,
6^(2n+1) - 6^2 = 6^3
Since, bases of all the three terms are same(,i.e.,6), thus, power should be equated.
(2n+1) - 2 = 3
2n + 1 = 3 + 2
2n = 5 -1
2n = 4
n = 2
Thus, value of n is 2
Hope it will help u.
Have a nice day.
monstermath:
Thank you!
Answered by
7
Hey!!!
We have 6^(2n + 1) - 36 = 6³
=> 6^(2n + 1) - 6² = 6³
Since both LHS and RHS side is in form of 6
=> 2n + 1 - 2 = 3
=> 2n = 4
=> n = 2
My answer may not be correct I'm solving such questions after a long gap
We have 6^(2n + 1) - 36 = 6³
=> 6^(2n + 1) - 6² = 6³
Since both LHS and RHS side is in form of 6
=> 2n + 1 - 2 = 3
=> 2n = 4
=> n = 2
My answer may not be correct I'm solving such questions after a long gap
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