If 6^2x-1-(36)^x-1=6480,find value of x
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6²ˣ⁻¹-36ˣ⁻¹=6480
=6²ˣ⁻¹-(6²)ˣ⁻¹=6480
=6²ˣ⁻¹-6²ˣ⁻²=6480
=6²ˣ(6⁻¹-6⁻²)=6480
=6²ˣ(1/6-1/36)=6480
=6²ˣ(6-1)/36=6480
=6²ˣ×5/36=6480
=6²ˣ=6480×36/5
=6²ˣ=1296×36
=6²ˣ=6⁴×6²
=6²ˣ=6⁶
Therefore 2x=6
=> x=3
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=6²ˣ⁻¹-(6²)ˣ⁻¹=6480
=6²ˣ⁻¹-6²ˣ⁻²=6480
=6²ˣ(6⁻¹-6⁻²)=6480
=6²ˣ(1/6-1/36)=6480
=6²ˣ(6-1)/36=6480
=6²ˣ×5/36=6480
=6²ˣ=6480×36/5
=6²ˣ=1296×36
=6²ˣ=6⁴×6²
=6²ˣ=6⁶
Therefore 2x=6
=> x=3
Plz follow me , if this answer helps plz mark as brainliest ..... Thanks
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