Question

if 6/(3√2-2√3)=(a√2+b√3),find the values of a and b​

Answer 1

Answer: a=3 , b= 2

Step-by-step explanation:

6/(3*2^1/2-2*3^1/2) = 6*(3*2^1/2+2*3^1/2)/(3*2^1/2-2*3^1/2)*(3*2^1/2+2*3^1/2) = 6*(3*2^1/2+2*3^1/2)/(18-12) = (3*2^1/2+2*3^1/2) hence,a=3,b=2

Answer 2

Answer:

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Step-by-step explanation:

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