Question

If
6.39 of Na HCO3are added to 10g of HCl. the residue is found to weigh 12g. what is the mass of CO2 released inthis reaction?
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Answer 1

Answer:

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Explanation:

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Answer 2

NaHCO3 + HCl → Residue + CO2

Weight of reactants = weight of NaHCO3 + weight of HCl

= 6.3 + 10 = 16.3g

Weight of product = weight of residue + weight of CO2

=12 + x

x → weight of CO2 released.

According to law of conservation of mass

Weight of reactants = weight of products

⇒16.3 = 12 + x

⇒x = 16.3 − 12 = 4.3g

∴ Weight of CO2 released =4.3g