If 6.3gm of NaHCO3 are added to 15.0gm of CH3COOH solution, the residue is found to weigh 18.0gm. What is the mass of CO2 released in the reaction..??
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The chemical reaction will be:
NaHCO
3
+CH
3
COOH→CH
3
COONa+H
2
O+CO
2
molarmass:
NaHCO
3
=84
CH
3
COOH=60
CH
3
COONa=82
CO
2
=44
84gNaHCO
3
+60gCH
3
COOH→82gCH
3
COONa+44gCO
2
Moles of NaHCO
3
=
84
6.3
=0.075
Moles of CH
3
COOH=
60
15
=0.25
∴NaHCO
3
is the limited reagent.
Moles of CO
2
formed=0.075
weight of CO
2
=0.075×44=3.3g
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