Question

if 6.84g of sugar(sucrose) is dissolved in 36 g of water,then total number of hydrogen atoms present in sugar solution will be (molecular weight of sucrose =342 u)

Answer 1

The answer is in the photo

Answer 2

Answer:Total number of hydrogen atoms present in sugar solution are $2.67376\times 10^{24}$ of hydrogen atoms.

Explanation:

1) Hydrogen atoms from sugar in solution:

Given mass of sucrose in sugar solution =  6.84 g

Moles of sugar solution= $\frac{\text{Given mass of sucrose}}{\text{Molecular mass of sucrose}}=\frac{6.84 g}{342 g/mol}=0.02 mol$

Number of sucrose molecule in 0.02moles = Number of moles of sucrose $\times N_A$=$0.02 mole\times 6.022\times 10^{23} (mol)^{-1}=1.2044\times 10^{22} \text{molecules of sucrose}$

$C_{12}H_{22}O_{11}$ is the molecular formula of sucrose and it contains  22 atoms of hydrogen.

Then$1.1405\times 10^{23} molecules$ of sucrose will contain =$22\times 1.2044\times 10^{22}=2.6496\times 10^{23}$ hydrogen atoms .

2) Hydrogen atoms from water in solution:

Given mass of water =  36 g

Moles of sugar solution= $\frac{\text{Given mass of sucrose}}{\text{Molecular mass of sucrose}}=\frac{36}{18}=2 mol$

Number of water molecules in 2 moles= Number of moles of water $\times N_A$ = $2 mole\times (6.022\times 10^{23} mol^{-1})=1.2044\times 10^{24}\text{water molecules}$.

$H_2O$ is the molecular formula of water and it contains 2 atoms of hydrogen.

Then $1.2044\times 10^{24} molecules$ of water will contain =$2\times 1.2044\times 10^{24}=2.4088\times 10^{24}$ hydrogen atoms .

3) Total number of hydrogen atoms present in sugar solution will be:

= (Hydrogen atoms from sugar in solution+Hydrogen atoms from water in solution)

= $2.6496\times 10^{23}+2.4088\times 10^{24}=2.67376\times 10^{24}$ of hydrogen atoms.