Question

If, 6-8x/x + 6-8y/y + 6-8z/z = 0
Then, 1/x+1/y+1/z = ?

Answer 1

$\frac{(6-8x)}{x} = \frac{6}{x} -8$

$\frac{(6-8y)}{y} = \frac{6}{y} -8$

$\frac{(6-8z)}{z} = \frac{6}{z} -8$

$\frac{(6-8x)}{x} + \frac{(6-8y)}{y} + \frac{(6-8z)}{z}=0$
$6[\frac{1}{x} + \frac{1}{y} + \frac{1}{z}] = 8+8+8$
$[\frac{1}{x} + \frac{1}{y} + \frac{1}{z}] = 24/6$

Answer 2

Answer:

Step-by-step explanation: