Question

if 6 by 3 root 2 minus 2 root 3 is equal to a root 2 + root 3 find the value of a and b

Answer 1

A/Q,
6/3√2-2√3=√2+√3
=√2-2√3=√2+√3
=2√3+√3=0
=√3[√2*√2+1]=0
then, √3=0, √2=-1/√2

Answer 2

lhs = (5+2√3)/(7+4√3)

= [(5+2√3)(7-4√3)]/[(7-4√3)(7+4√3)]
=[35-20√3+14√3-24]/[7²-(4√3)²]
=[11-6√3]/[49-48]
=11-6√3
therefore
11-6√3 = a+b√3

compare both sides
a= 11, b= -6