If 6 cot A+ 2 cosec A = cot A + 5 cosec A, then secA is
a) 4/5
b) 2/7
c) 5/3
d) 5/4
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Answer:
hey 6 cotA + 2 cosec A = cotA + 5cosec A
so, 6*cosA/sinA + 2/sinA = cosA/sinA + 5/sinA
= 5 cosA/sinA -3/sinA = 0
so, 5cos A-3/sinA =0
so , 5 cos A - 3 = 0
cos A = 3/5
hope this helps plz mark as brainliest
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