Question

If 6 dice are rolled, probability that all show different faces

Answer 1

Answer:

P(all numbers are different)=6/6,5/6,4/6,3/6,2/6,1/6

Step-by-step explanation:

Imagine you throw one after the other. You consider a throw as a success if the number is different from all previous numbers. You start with one. This is always a succes so P(first)=1=6/6. Your second throw is a success if one of the remaining 5 numbers shows, so P(second)=5/6. And so on. Since all the throws are independent, the total probability is the product of all separate probabilities:

P(all numbers are different)=6/6,5/6,4/6,3/6,2/6,1/6