If 6 is added with the tens digit and 4 is added to the unit digit of a two digit number, then the
new number so formed using new digits is 3 times than the original number. The original number is
(2) 128
(3) 32
(4) 45
(1) 64
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Answer:
let the original number be
tens. ones
x. y
so, it's value is 10x+y
after adding
tens. ones
x+6. y+4
it's value is (x+6)10 + (y+4)
as per given information
3(10x+y) = 10x + y + 64
=> 2(10x+y) = 64
=> 10x+y = 32
so, the original number is 32
VERIFICATION:-
Original number:- 32
after changes:- (3+6)(2+4) = 96
and new number formed is 3 times of original number [ 32×3 = 96 ]
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