Question

If 6 men and 8 boys can do a piece of work in 10 days,while 26men and 48 boys can do the same in 2days,the time taken by 15 men,and 20 boys in doing the same type of work will be,

Answer 1

Answer:

Step-by-step explanation:

Equations are solved in pic given below.

Let, 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y = 1/10

and 26x + 48y = 1/2

Solving these two equations, we get : x = 1/100 and y =1/200

=>(15 men + 20 boy)'s 1 day's work = =>15(1/100) + 20(1/200)

=>15/100 + 20/200

=>30/200 + 20/200

=>50/200

=>1/4

Thus, 15 men and 20 boys can do

the work in 4 days.

Answer 2

Answer:

Step-by-step explanation:

Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y = 1 and 26x + 48y = 1 .

10 2

Solving these two equations, we get : x = 1 and y = 1 .

100 200

(15 men + 20 boy)'s 1 day's work = 15 + 20 = 1 .

100 200 4

15 men and 20 boys can do the work in 4 days