Math, asked by mohanauligepal6642, 1 year ago

If 6^(x-3)=36^(x-5), then what is the value of X?
a,-1
b,2
c,7
d,No value will agree

Answers

Answered by Anonymous
3
The Answer would be c.







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Answered by VaibhavSR
0

Answer:

Then the Value of X is 7

Step-by-step explanation:

When  exponential phrases with the equal base are multiplied, their powers are introduced even as the bottom stays the equal. For example, allow us to multiply, 6³ × 6⁵ = 6(3 + 5) = 68. However, while  exponential phrases having the equal base are divided, their powers are subtracted. For example, 7⁸ ÷ 7⁵ = 73.

Given

6^(x-3)=36^(x-5),

To discover

we should discover the x value

6^ ( x-3) = 6² ^ ( x-5)

If bases are equal powers are need to be additionally equal

so the

x-3 = 2x-10

2x-x= 10-3

x=7

Then the Value of X is 7

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