If N = 82pow3 - 62pow3 -
20pow3 then N is divisible by:
a) 31 and 41
b) 13 and 67
c) 17 and 7
d) none
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Answer:
31 and 41
Step-by-step explanation:
N = 82^3 - 62^3 -20^3
N = 2^3 ( 41^3 - 31^3 - 10^3 )
N = 8 [ ( 41-31 ) ( 41^2 + 31^2 + 41*31 ) - 10^3 ]
[ ∵ a^3 - b^3 = (a-b)*{(a)^2 + (b)^2 + a*b)]
N = 80 ( 1681 + 961 + 1271 - 100 )
N = 80 ( 3813 )
N = 80 ( 41 ) ( 93 )
N = 80 "(41) (31)" 3
∴ N is divisible by both 41 and 31.
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