Question

If 62a1 is a multiple of 3, what is value of a?

Answer 1

We know that 62a1 is a multiple of 3..

So, by using divisibility rule of 3 for multiple 62a1 , the sum of all digits of the multiple

=6+2+a+1

=multiple of 3..

So, by placing digits from 0 to 9 we get the condition satisfied for the digits;;

for□ 0=6+2+0+1= 9 =multiple of 3

□ 3= 6+2+3+1= 12 = multiple of 3

□ 5= 6+2+6+1= 15 = multiple of 3

□ 9= 6+2+9+1=18 = multiple of 3

So,,,the values of a are 0,3,5 and 9...

Hope it helps u..(^__^)....