Question

If 64y8 is exactly divisible by 3

Answer 1

If 64y8 is divisible by 3, then
6+4+y+8 is divisible by 3
18+y is divisible by 3
So y can be 0, 3, 6 or 9

Answer 2

Please mark brainliest it helps.

Since 64y8 is divisible by 3, the sum of its digits is a multiple of 3.

6+4+y+8 = 18+y

18 is a multiple of 3.

18 - 18= y

0 = y

or, 21 -18 = y

3 = y.

so the value of y can be 0 and 3 both.