Math, asked by buntybeesa3943, 11 months ago

If 68/21 = x + 1/y+1/z then find x,y,z that belongs to natural number

Answers

Answered by utkarsh2447p
1

Answer is

x=47/21=2.24

y=47/21=2.24

z=68/21=3.24

that belongs to natural numbers

Answered by mkeerthi227
3

Hello

Solution :

68/ 21 = 3+5/21

= 3+1/21/5

= 3+1/4+1/5

Therefore , x = 3 , y = 4 , z = 5

Thank you

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